Optimal. Leaf size=327 \[ -\frac{\left (A b^2-a (b B-a C)\right ) \sqrt{c+d \tan (e+f x)}}{f \left (a^2+b^2\right ) (b c-a d) (a+b \tan (e+f x))}-\frac{\left (-a^2 b^2 (5 A d+2 B c-3 C d)+3 a^3 b B d+a^4 (-C) d+a b^3 (4 A c-B d-4 c C)+b^4 (2 B c-A d)\right ) \tanh ^{-1}\left (\frac{\sqrt{b} \sqrt{c+d \tan (e+f x)}}{\sqrt{b c-a d}}\right )}{\sqrt{b} f \left (a^2+b^2\right )^2 (b c-a d)^{3/2}}-\frac{(i A+B-i C) \tanh ^{-1}\left (\frac{\sqrt{c+d \tan (e+f x)}}{\sqrt{c-i d}}\right )}{f (a-i b)^2 \sqrt{c-i d}}-\frac{(B-i (A-C)) \tanh ^{-1}\left (\frac{\sqrt{c+d \tan (e+f x)}}{\sqrt{c+i d}}\right )}{f (a+i b)^2 \sqrt{c+i d}} \]
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Rubi [A] time = 1.37937, antiderivative size = 327, normalized size of antiderivative = 1., number of steps used = 12, number of rules used = 7, integrand size = 47, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.149, Rules used = {3649, 3653, 3539, 3537, 63, 208, 3634} \[ -\frac{\left (A b^2-a (b B-a C)\right ) \sqrt{c+d \tan (e+f x)}}{f \left (a^2+b^2\right ) (b c-a d) (a+b \tan (e+f x))}-\frac{\left (-a^2 b^2 (5 A d+2 B c-3 C d)+3 a^3 b B d+a^4 (-C) d+a b^3 (4 A c-B d-4 c C)+b^4 (2 B c-A d)\right ) \tanh ^{-1}\left (\frac{\sqrt{b} \sqrt{c+d \tan (e+f x)}}{\sqrt{b c-a d}}\right )}{\sqrt{b} f \left (a^2+b^2\right )^2 (b c-a d)^{3/2}}-\frac{(i A+B-i C) \tanh ^{-1}\left (\frac{\sqrt{c+d \tan (e+f x)}}{\sqrt{c-i d}}\right )}{f (a-i b)^2 \sqrt{c-i d}}-\frac{(B-i (A-C)) \tanh ^{-1}\left (\frac{\sqrt{c+d \tan (e+f x)}}{\sqrt{c+i d}}\right )}{f (a+i b)^2 \sqrt{c+i d}} \]
Antiderivative was successfully verified.
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Rule 3649
Rule 3653
Rule 3539
Rule 3537
Rule 63
Rule 208
Rule 3634
Rubi steps
\begin{align*} \int \frac{A+B \tan (e+f x)+C \tan ^2(e+f x)}{(a+b \tan (e+f x))^2 \sqrt{c+d \tan (e+f x)}} \, dx &=-\frac{\left (A b^2-a (b B-a C)\right ) \sqrt{c+d \tan (e+f x)}}{\left (a^2+b^2\right ) (b c-a d) f (a+b \tan (e+f x))}-\frac{\int \frac{\frac{1}{2} \left (A b^2 d-2 a A (b c-a d)-2 (b B-a C) \left (b c-\frac{a d}{2}\right )\right )+(A b-a B-b C) (b c-a d) \tan (e+f x)+\frac{1}{2} \left (A b^2-a (b B-a C)\right ) d \tan ^2(e+f x)}{(a+b \tan (e+f x)) \sqrt{c+d \tan (e+f x)}} \, dx}{\left (a^2+b^2\right ) (b c-a d)}\\ &=-\frac{\left (A b^2-a (b B-a C)\right ) \sqrt{c+d \tan (e+f x)}}{\left (a^2+b^2\right ) (b c-a d) f (a+b \tan (e+f x))}-\frac{\int \frac{-\left (2 a b B+a^2 (A-C)-b^2 (A-C)\right ) (b c-a d)-\left (a^2 B-b^2 B-2 a b (A-C)\right ) (b c-a d) \tan (e+f x)}{\sqrt{c+d \tan (e+f x)}} \, dx}{\left (a^2+b^2\right )^2 (b c-a d)}+\frac{\left (3 a^3 b B d-a^4 C d+b^4 (2 B c-A d)+a b^3 (4 A c-4 c C-B d)-a^2 b^2 (2 B c+5 A d-3 C d)\right ) \int \frac{1+\tan ^2(e+f x)}{(a+b \tan (e+f x)) \sqrt{c+d \tan (e+f x)}} \, dx}{2 \left (a^2+b^2\right )^2 (b c-a d)}\\ &=-\frac{\left (A b^2-a (b B-a C)\right ) \sqrt{c+d \tan (e+f x)}}{\left (a^2+b^2\right ) (b c-a d) f (a+b \tan (e+f x))}+\frac{(A-i B-C) \int \frac{1+i \tan (e+f x)}{\sqrt{c+d \tan (e+f x)}} \, dx}{2 (a-i b)^2}+\frac{(A+i B-C) \int \frac{1-i \tan (e+f x)}{\sqrt{c+d \tan (e+f x)}} \, dx}{2 (a+i b)^2}+\frac{\left (3 a^3 b B d-a^4 C d+b^4 (2 B c-A d)+a b^3 (4 A c-4 c C-B d)-a^2 b^2 (2 B c+5 A d-3 C d)\right ) \operatorname{Subst}\left (\int \frac{1}{(a+b x) \sqrt{c+d x}} \, dx,x,\tan (e+f x)\right )}{2 \left (a^2+b^2\right )^2 (b c-a d) f}\\ &=-\frac{\left (A b^2-a (b B-a C)\right ) \sqrt{c+d \tan (e+f x)}}{\left (a^2+b^2\right ) (b c-a d) f (a+b \tan (e+f x))}-\frac{(i (A+i B-C)) \operatorname{Subst}\left (\int \frac{1}{(-1+x) \sqrt{c+i d x}} \, dx,x,-i \tan (e+f x)\right )}{2 (a+i b)^2 f}+\frac{(i A+B-i C) \operatorname{Subst}\left (\int \frac{1}{(-1+x) \sqrt{c-i d x}} \, dx,x,i \tan (e+f x)\right )}{2 (a-i b)^2 f}+\frac{\left (3 a^3 b B d-a^4 C d+b^4 (2 B c-A d)+a b^3 (4 A c-4 c C-B d)-a^2 b^2 (2 B c+5 A d-3 C d)\right ) \operatorname{Subst}\left (\int \frac{1}{a-\frac{b c}{d}+\frac{b x^2}{d}} \, dx,x,\sqrt{c+d \tan (e+f x)}\right )}{\left (a^2+b^2\right )^2 d (b c-a d) f}\\ &=-\frac{\left (3 a^3 b B d-a^4 C d+b^4 (2 B c-A d)+a b^3 (4 A c-4 c C-B d)-a^2 b^2 (2 B c+5 A d-3 C d)\right ) \tanh ^{-1}\left (\frac{\sqrt{b} \sqrt{c+d \tan (e+f x)}}{\sqrt{b c-a d}}\right )}{\sqrt{b} \left (a^2+b^2\right )^2 (b c-a d)^{3/2} f}-\frac{\left (A b^2-a (b B-a C)\right ) \sqrt{c+d \tan (e+f x)}}{\left (a^2+b^2\right ) (b c-a d) f (a+b \tan (e+f x))}-\frac{(A-i B-C) \operatorname{Subst}\left (\int \frac{1}{-1-\frac{i c}{d}+\frac{i x^2}{d}} \, dx,x,\sqrt{c+d \tan (e+f x)}\right )}{(a-i b)^2 d f}-\frac{(A+i B-C) \operatorname{Subst}\left (\int \frac{1}{-1+\frac{i c}{d}-\frac{i x^2}{d}} \, dx,x,\sqrt{c+d \tan (e+f x)}\right )}{(a+i b)^2 d f}\\ &=-\frac{(i A+B-i C) \tanh ^{-1}\left (\frac{\sqrt{c+d \tan (e+f x)}}{\sqrt{c-i d}}\right )}{(a-i b)^2 \sqrt{c-i d} f}-\frac{(B-i (A-C)) \tanh ^{-1}\left (\frac{\sqrt{c+d \tan (e+f x)}}{\sqrt{c+i d}}\right )}{(a+i b)^2 \sqrt{c+i d} f}-\frac{\left (3 a^3 b B d-a^4 C d+b^4 (2 B c-A d)+a b^3 (4 A c-4 c C-B d)-a^2 b^2 (2 B c+5 A d-3 C d)\right ) \tanh ^{-1}\left (\frac{\sqrt{b} \sqrt{c+d \tan (e+f x)}}{\sqrt{b c-a d}}\right )}{\sqrt{b} \left (a^2+b^2\right )^2 (b c-a d)^{3/2} f}-\frac{\left (A b^2-a (b B-a C)\right ) \sqrt{c+d \tan (e+f x)}}{\left (a^2+b^2\right ) (b c-a d) f (a+b \tan (e+f x))}\\ \end{align*}
Mathematica [A] time = 6.21476, size = 521, normalized size = 1.59 \[ -\frac{\left (A b^2-a (b B-a C)\right ) \sqrt{c+d \tan (e+f x)}}{f \left (a^2+b^2\right ) (b c-a d) (a+b \tan (e+f x))}-\frac{\frac{2 \sqrt{b c-a d} \left (\frac{1}{2} a^2 d \left (A b^2-a (b B-a C)\right )+\frac{1}{2} b^2 \left (-2 a A (b c-a d)-2 (b B-a C) \left (b c-\frac{a d}{2}\right )+A b^2 d\right )-a b (b c-a d) (-a B+A b-b C)\right ) \tanh ^{-1}\left (\frac{\sqrt{b} \sqrt{c+d \tan (e+f x)}}{\sqrt{b c-a d}}\right )}{\sqrt{b} f \left (a^2+b^2\right ) (a d-b c)}+\frac{\frac{i \sqrt{c-i d} \left (-(b c-a d) \left (a^2 (A-C)+2 a b B-b^2 (A-C)\right )+i (b c-a d) \left (a^2 B-2 a b (A-C)-b^2 B\right )\right ) \tanh ^{-1}\left (\frac{\sqrt{c+d \tan (e+f x)}}{\sqrt{c-i d}}\right )}{f (-c+i d)}-\frac{i \sqrt{c+i d} \left (-(b c-a d) \left (a^2 (A-C)+2 a b B-b^2 (A-C)\right )-i (b c-a d) \left (a^2 B-2 a b (A-C)-b^2 B\right )\right ) \tanh ^{-1}\left (\frac{\sqrt{c+d \tan (e+f x)}}{\sqrt{c+i d}}\right )}{f (-c-i d)}}{a^2+b^2}}{\left (a^2+b^2\right ) (b c-a d)} \]
Antiderivative was successfully verified.
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Maple [B] time = 0.222, size = 20870, normalized size = 63.8 \begin{align*} \text{output too large to display} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F(-2)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Exception raised: ValueError} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{A + B \tan{\left (e + f x \right )} + C \tan ^{2}{\left (e + f x \right )}}{\left (a + b \tan{\left (e + f x \right )}\right )^{2} \sqrt{c + d \tan{\left (e + f x \right )}}}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{C \tan \left (f x + e\right )^{2} + B \tan \left (f x + e\right ) + A}{{\left (b \tan \left (f x + e\right ) + a\right )}^{2} \sqrt{d \tan \left (f x + e\right ) + c}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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